Given:
The word ‘MONDAY’
Total letters = 6
(i) 4 letters are used at a time
Number of ways = (No. of ways of choosing 4 letters from MONDAY)
= (6C4)
By using the formula,
nCr =\( \dfrac{ n!}{r!(n – r)!}\)
6C4 = \(\dfrac{ 6! }{ 4!(6 – 4)!}\)
= 3×5
= 15
Now we need to find the no. of words that can be formed by 4 letters.
15 × 4! = 15 × (4×3×2×1)
= 15 × 24
= 360
The no. of words that can be formed by 4 letters of MONDAY is 360.
(ii) all letters are used at a time
Total number of letters in the word ‘MONDAY’ is 6
So, the total no. of words that can be formed is 6! = 360
The no. of words that can be formed by 6 letters of MONDAY is 360.
(iii) all letters are used but first letter is a vowel ?
In the word ‘MONDAY’ the vowels are O and A. We need to choose one vowel from these 2 vowels for the first place of the word.
So,
Number of ways = (No. of ways of choosing a vowel from 2 vowels)
= (2C1)
By using the formula,
nCr =\( \dfrac{ n!}{r!(n – r)!}\)
2C1 = \( \dfrac{2! }{ 1!(2 – 1)!}\)
= (2×1)
= 2
Now we need to find the no. of words that can be formed by remaining 5 letters.
2 × 5! = 2 × (5×4×3×2×1)
= 2 × 120
= 240
The no. of words that can be formed by all letters of MONDAY in which the first letter is a vowel is 240.
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