(i) (-2, 3, 4)
Since we need to find its image in yz-plane, a sign of its x-coordinate will change
So, Image of point (-2, 3, 4) is (2, 3, 4)
(ii)(-5, 4, -3)
Since we need to find its image in xz-plane, sign of its y-coordinate will change
So, Image of point (-5, 4, -3) is (-5, -4, -3)
(iii) (5, 2, -7)
Since we need to find its image in xy-plane, a sign of its z-coordinate will change
So, Image of point (5, 2, -7) is (5, 2, 7)
(iv) (-5, 0, 3)
Since we need to find its image in xz-plane, sign of its y-coordinate will change
So, Image of point (-5, 0, 3) is (-5, 0, 3)
(v) (-4, 0, 0)
Since we need to find its image in xy-plane, sign of its z-coordinate will change
So, Image of point (-4, 0, 0) is (-4, 0, 0)
Answered by Aaryan | 1 year agoA(1, 2, 3), B(0, 4, 1), C(-1, -1, -3) are the vertices of a triangle ABC. Find the point in which the bisector of the angle ∠BAC meets BC.
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