Given:
The points (1, 5, 7) and (5, 1, -4)
We know x = 0 and y = 0 on z-axis
Let R(0, 0, z) any point on z-axis
According to the question:
RA = RB
RA2 = RB2
By using the formula,
The distance between any two points (a, b, c) and (m, n, o) is given by,
We know, RA2 = RB2
26+ (z – 7)2 = (z + 4)2 + 26
z2+ 49 – 14z + 26
= z2+ 16 + 8z + 26
49 – 14z = 16 + 8z
49 – 16 = 14z + 8z
22z = 33
z =\( \dfrac{33}{22}\)
= \( \dfrac{3}{2}\)
The point R (0, 0,\( \dfrac{3}{2}\)) on z-axis is equidistant from (1, 5, 7) and (5, 1, -4).
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