Find the point on y-axis which is equidistant from the points (3, 1, 2) and (5, 5, 2).

Asked by Sakshi | 1 year ago |  30

##### Solution :-

Given:

The points (3, 1, 2) and (5, 5, 2)

We know x = 0 and z = 0 on y-axis

Let R(0, y, 0) any point on the y-axis

According to the question:

RA = RB

RA2 = RB2

By using the formula,

The distance between any two points (a, b, c) and (m, n, o) is given by, So, We know, RA2 = RB2

13+ (y – 1)2 = (y – 5)2 + 29

y2+ 1 – 2y + 13

= y2+ 25 – 10y + 29

10y – 2y = 54 – 14

8y = 40

y = $$\dfrac{40}{8}$$

= 5

The point R (0, 5, 0) on y-axis is equidistant from (3, 1, 2) and (5, 5, 2).

Answered by Aaryan | 1 year ago

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