Show that the points (0, 7, 10), (-1, 6, 6) and (-4, 9, 6) are the vertices of an isosceles right-angled triangle.

Asked by Sakshi | 1 year ago |  46

1 Answer

Solution :-

Given:

The points (0, 7, 10), (-1, 6, 6) and (-4, 9, 6)

Isosceles right-angled triangle is a triangle whose two sides are equal and also satisfies Pythagoras Theorem.

By using the formula,

The distance between any two points (a, b, c) and (m, n, o) is given by,

RD Sharma Solutions for Class 11 Maths Chapter 28 – image 28

RD Sharma Solutions for Class 11 Maths Chapter 28 – image 29

Since, AB = BC

So, AB2 + BC2

= \( (3\sqrt{2})^2 + (3\sqrt{2})^2\)

= 18 + 18

= 36

= AC2

We know that, AB = BC and AB2 + BC2 = AC2

So, Δ ABC is an isosceles-right angled triangle

Hence Proved.

Answered by Aaryan | 1 year ago

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