Given:
The points (0, 7, 10), (-1, 6, 6) and (-4, 9, 6)
Isosceles right-angled triangle is a triangle whose two sides are equal and also satisfies Pythagoras Theorem.
By using the formula,
The distance between any two points (a, b, c) and (m, n, o) is given by,
Since, AB = BC
So, AB2 + BC2
= \( (3\sqrt{2})^2 + (3\sqrt{2})^2\)
= 18 + 18
= 36
= AC2
We know that, AB = BC and AB2 + BC2 = AC2
So, Δ ABC is an isosceles-right angled triangle
Hence Proved.
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