1 Answer
Solution :-
Given:
The vertices of the triangle are A (5, 4, 6), B (1, -1, 3) and C (4, 3, 2).
By using the formulas let us find the coordinates of D and the length of AD
The distance between any two points (a, b, c) and (m, n, o) is given by,
The distance between A (5, 4, 6), B (1, -1, 3) is AB
\( \sqrt{(5-2)^2+4-(-1)^2+(6-3)^2}\)
\( \sqrt{16+25+9}=5\sqrt{2}\)
The distance between A (5, 4, 6), C (4, 3, 2) is AC
\( \sqrt{(5-4)^2+(4-3)^2+(6-2)^2}\)
\( \sqrt{1+1+16}=3\sqrt{2}\)
AB : AC = 5:3
BD: DC = 5:3
So, m = 5 and n = 3
B(1, -1, 3) and C(4, 3, 2)
Coordinates of D using section formula:
The coordinates of D are \(( \dfrac{23}{8},\dfrac{3}{2},\dfrac{19}{8})\)
Answered by Aaryan | 1 year agoRelated Questions
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