1 Answer
Solution :-
Given:
The points A (2, -3, 4) and B (8, 0, 10)
Let Point C(x, y, 8), and C divides AB in ratio k: 1
So, m = k and n = 1
A(2, -3, 4) and B(8, 0, 10)
Coordinates of C are:
On comparing we get,
\(\dfrac{ [10k + 4] }{ [k + 1]}\) = 8
10k + 4 = 8(k + 1)
10k + 4 = 8k + 8
10k – 8k = 8 – 4
2k = 4
k = \( \dfrac{4}{2}\)
= 2
Here C divides AB in ratio 2:1
x =\(\dfrac{ [8k + 2] }{ [k + 1]}\)
=\( \dfrac{ [8(2) + 2] }{ [2 + 1]}\)
=\( \dfrac{[16 + 2] }{ [3]}\)
= \( \dfrac{18}{3}\)
= 6
y = \( \dfrac{-3 }{ [k + 1]}\)
=\( \dfrac{-3 }{ [2 + 1]}\)
= \( \dfrac{-3}{3}\)
= -1
The Coordinates of C are (6, -1, 8).
Answered by Aaryan | 1 year agoRelated Questions
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