1 Answer
Solution :-
Given:
The points (2, 4, 5) and (3, 5, 4)
We know X coordinate is always 0 on yz-plane
So, let Point C(0, y, z), and let C divide AB in ratio k: 1
Then, m = k and n = 1
A(2, 4, 5) and B(3, 5, 4)
The coordinates of C are:
On comparing we get,
\(\dfrac{ [3k + 2] }{ [k + 1] }\)= 0
3k + 2 = 0(k + 1)
3k + 2 = 0
3k = – 2
k = \( \dfrac{-2}{3}\)
We can say that, C divides AB externally in ratio 2: 3
Answered by Aaryan | 1 year agoRelated Questions
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