Given: A die is thrown.
The total number of outcomes is six, n (S) = 6
(i) Let E be the event of getting a prime number
E = {2, 3, 5}
n (E) = 3
P (E) = \( \dfrac{ n (E) }{ n (S)}\)
= \( \dfrac{3}{6}\)
= \( \dfrac{1}{2}\)
(ii) Let E be the event of getting 2 or 4
E = {2, 4}
n (E) = 2
P (E) = \( \dfrac{ n (E) }{ n (S)}\)
= \( \dfrac{2}{6}\)
= \( \dfrac{1}{3}\)
(iii) Let E be the event of getting a multiple of 2 or 3
E = {2, 3, 4, 6}
n (E) = 4
P (E) = \( \dfrac{ n (E) }{ n (S)}\)
= \( \dfrac{4}{6}\)
= \( \dfrac{2}{3}\)
Answered by Aaryan | 1 year agoOne number is chosen from numbers 1 to 100. Find the probability that it is divisible by 4 or 6?
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