What is the probability that a leap year has 53 Sundays and 53 Mondays?

Asked by Aaryan | 1 year ago |  50

##### Solution :-

Given: A leap year which includes 52 weeks and two days

So, we now have to determine the probability of that remaining two days is Sunday and Monday

S = {MT, TW, WT, TF, FS, SSu, SuM}

n (S) = 7

E= {SuM}

n (E) = 1

P (E) = $$\dfrac{ n (E) }{ n (S)}$$

$$\dfrac{ 1} {7}$$

Answered by Aaryan | 1 year ago

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