Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice is greater than 10

Asked by Aaryan | 1 year ago |  45

##### Solution :-

Given: Two unbiased dice are thrown.

So, we now have to determine the probability of getting the sum of digits on dice greater than 10

Total number of possible outcomes is 62=36

n (S) = 36

Let E be the event of getting same number on all the three dice

E = {(5,6) (6,5) (6,6)}

n (E) = 3

P (E) = $$\dfrac{ n (E) }{ n (S)}$$

=$$\dfrac{3 }{ 36}$$

$$\dfrac{ 1 }{ 12}$$

Answered by Aaryan | 1 year ago

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