In shutting a pack of 52 playing cards, four are accidently dropped; find the chance that the missing cards should be one from each suit

Asked by Aaryan | 1 year ago |  60

##### Solution :-

Given: A pack of 52 cards from which 4 are dropped.

We now have to find the probability that the missing cards should be one from each suit

We know that, from well shuffled pack of cards, 4 cards missed out total possible outcomes are

n (S) = 52C= 270725

Let E be the event that four missing cards are from each suite

n (E) = 13C1×13C1×13C1×13C= 134

P (E) = $$\dfrac{ n (E) }{ n (S)}$$

= $$\dfrac{13^4 }{ 270725}$$

= $$\dfrac{ 2197}{20825}$$

Answered by Aaryan | 1 year ago

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