Given: A pack of 52 cards from which 4 are dropped.
We now have to find the probability that the missing cards should be one from each suit
We know that, from well shuffled pack of cards, 4 cards missed out total possible outcomes are
n (S) = 52C4 = 270725
Let E be the event that four missing cards are from each suite
n (E) = 13C1×13C1×13C1×13C1 = 134
P (E) = \( \dfrac{ n (E) }{ n (S)}\)
= \( \dfrac{13^4 }{ 270725}\)
= \(\dfrac{ 2197}{20825}\)
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