A bag contains 6 red, 4 white and 8 blue balls. If three balls are drawn at random, find the probability that one is red, one is white and one is blue

Asked by Aaryan | 1 year ago |  41

##### Solution :-

Given: A bag containing 6 red, 4 white and 8 blue balls.

By using the formula,

P (E) = $$\dfrac{favourable\; outcomes }{total\; possible\; outcomes}$$

Three balls are drawn so, we have to find the probability that one is red, one is white and one is blue.

Total number of outcomes for drawing 3 balls is 18C3

n (S) = 18C= 816

Let E be the event that one red, one white and one blue ball is drawn.

n (E) = 6C14C18C= 192

P (E) =$$\dfrac{ n (E) }{ n (S)}$$

$$\dfrac{192}{816}$$

$$\dfrac{4}{17}$$

Answered by Aaryan | 1 year ago

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