The face cards are removed from a full pack. Out of the remaining 40 cards, 4 are drawn at random. What is the probability that they belong to different suits?

Asked by Aaryan | 1 year ago |  31

##### Solution :-

Given: The face cards are removed from a full pack of 52.

By using the formula,

P (E) = $$\dfrac{favourable\; outcomes }{total\; possible\; outcomes}$$

Four cards are drawn from the remaining 40 cards, so we have to find the probability that all of them belong to different suit.

Total possible outcomes of drawing four cards are 40C4

n (S) =  40C4 = 91390

Let E be the event that 4 cards belong to different suit.

n (E) = 10C110C110C110C= 10000

P (E) =$$\dfrac{ n (E) }{ n (S)}$$

= $$\dfrac{ 10000 }{ 91390}$$

$$\dfrac{ 1000 }{ 9139}$$

Answered by Aaryan | 1 year ago

### Related Questions

#### One number is chosen from numbers 1 to 100. Find the probability that it is divisible by 4 or 6?

One number is chosen from numbers 1 to 100. Find the probability that it is divisible by 4 or 6?

#### The probability that a student will pass the final examination in both English and Hindi is 0.5

The probability that a student will pass the final examination in both English and Hindi is 0.5 and the probability of passing neither is 0.1. If the probability of passing the English examination is 0.75. What is the probability of passing the Hindi examination?

#### A card is drawn from a deck of 52 cards. Find the probability of getting an ace or a spade card.

A card is drawn from a deck of 52 cards. Find the probability of getting an ace or a spade card.