Given: There are four men and six women on the city councils.

By using the formula,

P (E) =\( \dfrac{favourable\; outcomes }{total\; possible\; outcomes}\)

From the city council one person is selected as a council member so, we have to find the probability that it is a woman.

Total possible outcomes of selecting a person is ^{10}C_{1}

n (S)= ^{10}C_{1} = 10

Let E be the event that it is a woman

n (E) = ^{6}C_{1 }= 6

P (E) =\( \dfrac{ n (E) }{ n (S)}\)

=\( \dfrac{6}{10}\)

= \( \dfrac{3}{5}\)

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