There are four men and six women on the city councils. If one council member is selected for a committee at random, how likely is that it is a women?

Asked by Aaryan | 1 year ago |  34

##### Solution :-

Given: There are four men and six women on the city councils.

By using the formula,

P (E) =$$\dfrac{favourable\; outcomes }{total\; possible\; outcomes}$$

From the city council one person is selected as a council member so, we have to find the probability that it is a woman.

Total possible outcomes of selecting a person is 10C1

n (S)= 10C1 = 10

Let E be the event that it is a woman

n (E) = 6C= 6

P (E) =$$\dfrac{ n (E) }{ n (S)}$$

=$$\dfrac{6}{10}$$

$$\dfrac{3}{5}$$

Answered by Aaryan | 1 year ago

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