Solve: 12x < 50, when

(i) x ∈ R

(ii) x ∈ Z

(iii) x ∈ N

Asked by Aaryan | 2 years ago |  86

1 Answer

Solution :-

Given:

12x < 50

So when we divide by 12, we get

\(\dfrac{ 12x}{ 12} < \dfrac{50}{12}\)

x <\( \dfrac{25}{6}\)

(i) x ∈ R

When x is a real number, the solution of the given inequation is (-∞, \( \dfrac{25}{6}\)).

(ii) x ∈ Z

When, 4 <\( \dfrac{25}{6}\) < 5

So when, when x is an integer, the maximum possible value of x is 4.

The solution of the given inequation is {…, –2, –1, 0, 1, 2, 3, 4}.

(iii) x ∈ N

When, 4 < \( \dfrac{25}{6}\) < 5

So when, when x is a natural number, the maximum possible value of x is 4. We know that the natural numbers start from 1, the solution of the given inequation is {1, 2, 3, 4}.

Answered by Aaryan | 2 years ago

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