Given:
12x < 50
So when we divide by 12, we get
\(\dfrac{ 12x}{ 12} < \dfrac{50}{12}\)
x <\( \dfrac{25}{6}\)
(i) x ∈ R
When x is a real number, the solution of the given inequation is (-∞, \( \dfrac{25}{6}\)).
(ii) x ∈ Z
When, 4 <\( \dfrac{25}{6}\) < 5
So when, when x is an integer, the maximum possible value of x is 4.
The solution of the given inequation is {…, –2, –1, 0, 1, 2, 3, 4}.
(iii) x ∈ N
When, 4 < \( \dfrac{25}{6}\) < 5
So when, when x is a natural number, the maximum possible value of x is 4. We know that the natural numbers start from 1, the solution of the given inequation is {1, 2, 3, 4}.
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