Solve: -4x > 30, when

(i) x ∈ R

(ii) x ∈ Z

(iii) x ∈ N

Asked by Aaryan | 1 year ago |  56

1 Answer

Solution :-

Given:

-4x > 30

So when we divide by 4, we get

\(\dfrac{-4x}{4} > \dfrac{30}{4}\)

-x > \( \dfrac{15}{2}\)

x < \( \dfrac{-15}{2}\)

(i) x ∈ R

When x is a real number, the solution of the given inequation is (-∞,\( \dfrac{-15}{2}\)).

(ii) x ∈ Z

When, -8 < \( \dfrac{-15}{2}\) < -7

So when, when x is an integer, the maximum possible value of x is -8.

The solution of the given inequation is {…, –11, –10, -9, -8}.

(iii) x ∈ N

As natural numbers start from 1 and can never be negative, when x is a natural number, the solution of the given inequation is ∅.

Answered by Aaryan | 1 year ago

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