\( 6 – 2x ≥ \dfrac{x}{5} + 4\)

\(\dfrac{ 6 – 2x ≥ (x+20)}{5}\)

5(6 – 2x) ≥ (x + 20)

30 – 10x ≥ x + 20

30 – 20 ≥ x + 10x

10 ≥11x

11x ≤ 10

Divide both sides by 11, we get

\(\dfrac{ 11x}{11} ≤ \dfrac{10}{11}\)

x ≤ \( \dfrac{10}{11}\)

The solution of the given inequation is (-∞, \( \dfrac{10}{11}\)).

Answered by Aaryan | 1 year agoSolve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.

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