Multiply both the sides by 5 we get,
\(\dfrac{ (3x – 2)}{5} × 5 ≤\dfrac{ (4x – 3)}{2} × 5\)
\( 3x – 2 ≤ \dfrac{(20x – 15)}{2}\)
Multiply both the sides by 2 we get,
\( (3x – 2) × 2 ≤ \dfrac{(20x – 15)}{2} × 2\)
6x – 4 ≤ 20x – 15
20x – 15 ≥ 6x – 4
20x – 15 + 15 ≥ 6x – 4 + 15
20x ≥ 6x + 11
20x – 6x ≥ 6x + 11 – 6x
14x ≥ 11
Divide both sides by 14, we get
\(\dfrac{ 14x}{14} ≥ \dfrac{11}{14}\)
x ≥ \( \dfrac{11}{14}\)
The solution of the given inequation is (\( \dfrac{11}{14}\), ∞).
Answered by Aaryan | 1 year agoSolve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.
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