\( \dfrac{x}{5} <(\dfrac{15x – 10 – 20x + 12}{20})\)
Multiply both the sides by 20 we get,
\( \dfrac{x}{5} × 20 < \dfrac{2 – 5x}{20} × 20\)
4x < 2 – 5x
4x + 5x < 2 – 5x + 5x
9x < 2
Divide both sides by 9, we get
\(\dfrac{ 9x}{9} <\dfrac{ 2}{9}\)
x < \( \dfrac{ 2}{9}\)
The solution of the given inequation is (-∞, \( \dfrac{ 2}{9}\)).
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