$$\dfrac{ x}{5} < \dfrac{(3x-2)}{4} – \dfrac{(5x-3)}{5}$$

Asked by Aaryan | 1 year ago |  152

##### Solution :-

$$\dfrac{x}{5} <(\dfrac{15x – 10 – 20x + 12}{20})$$

Multiply both the sides by 20 we get,

$$\dfrac{x}{5} × 20 < \dfrac{2 – 5x}{20} × 20$$

4x < 2 – 5x

4x + 5x < 2 – 5x + 5x

9x < 2

Divide both sides by 9, we get

$$\dfrac{ 9x}{9} <\dfrac{ 2}{9}$$

x < $$\dfrac{ 2}{9}$$

The solution of the given inequation is (-∞, $$\dfrac{ 2}{9}$$).

Answered by Aaryan | 1 year ago

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