\( \dfrac{x}{5} <(\dfrac{15x – 10 – 20x + 12}{20})\)

Multiply both the sides by 20 we get,

\( \dfrac{x}{5} × 20 < \dfrac{2 – 5x}{20} × 20\)

4x < 2 – 5x

4x + 5x < 2 – 5x + 5x

9x < 2

Divide both sides by 9, we get

\(\dfrac{ 9x}{9} <\dfrac{ 2}{9}\)

x < \( \dfrac{ 2}{9}\)

The solution of the given inequation is (-∞, \( \dfrac{ 2}{9}\)).

Answered by Aaryan | 1 year agoSolve each of the following in equations and represent the solution set on the number line \( \dfrac{5x}{4}-\dfrac{4x-1}{3}>1,\) where x ϵ R.

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