$$\dfrac{2(x-1)}{5} ≤ \dfrac{3(2+x)}{7}$$

Asked by Aaryan | 1 year ago |  157

##### Solution :-

Given:

Multiply both the sides by 5 we get,

$$\dfrac{ (2x – 2)}{5} × 5 ≤ \dfrac{(6 + 3x)}{7} × 5$$

2x – 2 ≤ 5(6 + 3x)/7

7 (2x – 2) ≤ 5 (6 + 3x)

14x – 14 ≤ 30 + 15x

14x – 14 + 14 ≤ 30 + 15x + 14

14x ≤ 44 + 15x

14x – 44 ≤ 44 + 15x – 44

14x – 44 ≤ 15x

15x ≥ 14x – 44

15x – 14x ≥ 14x – 44 – 14x

x ≥ –44

The solution of the given inequation is (–44, ∞).

Answered by Aaryan | 1 year ago

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