Given:
Multiply both the sides by 5 we get,
\(\dfrac{ (2x – 2)}{5} × 5 ≤ \dfrac{(6 + 3x)}{7} × 5\)
2x – 2 ≤ 5(6 + 3x)/7
7 (2x – 2) ≤ 5 (6 + 3x)
14x – 14 ≤ 30 + 15x
14x – 14 + 14 ≤ 30 + 15x + 14
14x ≤ 44 + 15x
14x – 44 ≤ 44 + 15x – 44
14x – 44 ≤ 15x
15x ≥ 14x – 44
15x – 14x ≥ 14x – 44 – 14x
x ≥ –44
The solution of the given inequation is (–44, ∞).
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