Find the values of trigonometric ratios \( cos \dfrac{19π}{6}\)

Asked by Sakshi | 1 year ago |  71

1 Answer

Solution :-

= cos 570°

= cos (90×6 + 30)°

Since, 570°  lies in III quadrant in which cosine function is negative.

cos 570° = cos (90×6 + 30)°

= – cos 30°

\( -\dfrac{\sqrt{3}}{2}\)

Answered by Sakshi | 1 year ago

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