Evaluate the \(\dfrac{ 1}{i^{58}}\)

Asked by Aaryan | 1 year ago |  106

1 Answer

Solution :-

Let us simplify we get,

= \( \dfrac{1}{ i^{56+2}}\)

= \( \dfrac{1}{ i^{56}}\) × i2

=\(\dfrac{ 1}{ (i^4)^{14}}\) × i2

= \( \dfrac{1}{-1}\) [since, i2 = -1]

= -1

Answered by Aaryan | 1 year ago

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