Evaluate the  i49 + i68 + i89 + i110

Asked by Aaryan | 1 year ago |  69

1 Answer

Solution :-

Let us simplify we get,

i49 + i68 + i89 + i110 = i(48 + 1) + i68 + i(88 + 1) + i(116 + 2)

= (i4)12×i + (i4)17 + (i4)22×i + (i4)29×i2

= i + 1 + i – 1

= 2i

Answered by Aaryan | 1 year ago

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