Find the values of the expressions i49 + i68 + i89 + i110

Asked by Sakshi | 1 year ago |  80

1 Answer

Solution :-

i49 + i68 + i89 + i110

Let us simplify we get,

i49 + i68 + i89 + i110 = i (48 + 1) + i68 + i(88 + 1) + i(108 + 2)

= (i4)12 × i + (i4)17 + (i4)22 × i + (i4)27 × i2

= i + 1 + i – 1 [since i4 = 1, i2 = – 1]

= 2i

 i49 + i68 + i89 + i110 = 2i

Answered by Aaryan | 1 year ago

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