Let us simplify and express in the standard form of (a + ib),
=\(\dfrac{ (2^3 + i^3 + 3(2)^2(i) + 3(i)^2(2)) }{(2 + 3i)}\)
= \(\dfrac{ (2 + 11i) }{ (2 + 3i)}\)
[multiply and divide with (2-3i)]
=\(\dfrac{ (2 + 11i)}{(2 + 3i)} × \dfrac{(2-3i)}{(2-3i)}\)
= \(\dfrac{ (4 + 16i – 33(-1)) }{ (4 – 9(-1))}\) [since, i2 = -1]
= \(\dfrac{ (37 + 16i) }{ 13}\)
The values of a, b are \(\dfrac{ 37}{13}, \dfrac{16}{13}\)
Answered by Aaryan | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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