(1 + i) (x + iy) = 2 – 5i
Given:
(1 + i) (x + iy) = 2 – 5i
Divide with (1+i) on both the sides we get,
(x + iy) = \(\dfrac{ (2 – 5i)}{(1+i)}\)
Multiply and divide by (1-i)
= \( \dfrac{2 – 7i + 5(-1) }{ 2}\) [since, i2 = -1]
= \(\dfrac{ (-3-7i)}{2}\)
Now, equating Real and Imaginary parts on both sides we get
x = \( \dfrac{-3}{2}\) and y = \( \dfrac{-7}{2}\)
Thee real values of x and y are \( \dfrac{-3}{2}, \dfrac{-7}{2}\)
Answered by Aaryan | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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