Given:
\( \dfrac{1}{(3 + 5i)}\)
Since the given complex number is not in the standard form of (a + ib)
Let us convert to standard form by multiplying and dividing with (3 – 5i)
We get,
\( \dfrac{1}{(3 + 5i)}\times \dfrac{3-5i}{(3 - 5i)}\)
\( =\dfrac{3-5i}{34}\)
We know the conjugate of a complex number (a + ib) is (a – ib)
So,
The conjugate of \( =\dfrac{3-5i}{34}\) is \( =\dfrac{3+5i}{34}\)
Answered by Aaryan | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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