Given: 9x2 + 4 = 0
9x2 + 4 × 1 = 0
We know, i2 = –1 = 1 = –i2
By substituting 1 = –i2 in the above equation, we get
So,
9x2 + 4(–i2) = 0
9x2 – 4i2 = 0
(3x)2 – (2i)2 = 0
[By using the formula, a2 – b2 = (a + b) (a – b)]
(3x + 2i) (3x – 2i) = 0
3x + 2i = 0 or 3x – 2i = 0
3x = –2i or 3x = 2i
x = \( \dfrac{-2i}{3}\) or x =\( \dfrac{2i}{3}\)
The roots of the given equation are \( \dfrac{-2i}{3}, \dfrac{2i}{3}\)
Answered by Aaryan | 1 year agoShow that 1 + i10 + i20 + i30 is a real number?
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