Solve the quadratic equations by factorization method only 6x2 – 17ix – 12 = 0

Asked by Sakshi | 1 year ago |  175

##### Solution :-

6x2 – 17ix – 12 = 0

Given: 6x2 – 17ix – 12 = 0

6x2 – 17ix – 12 × 1 = 0

We know, i2 = –1 ⇒ 1 = –i2

By substituting 1 = –i2 in the above equation, we get

6x2 – 17ix – 12(–i2) = 0

6x2 – 17ix + 12i2 = 0

6x2 – 9ix – 8ix + 12i2 = 0

3x(2x – 3i) – 4i(2x – 3i) = 0

(2x – 3i) (3x – 4i) = 0

2x – 3i = 0 or 3x – 4i = 0

2x = 3i or 3x = 4i

x = $$\dfrac{3i}{2}$$ or x = $$\dfrac{4i}{3}$$

The roots of the given equation are $$\dfrac{3i}{2}$$$$\dfrac{4i}{3}$$

Answered by Aaryan | 1 year ago

### Related Questions

#### Show that 1 + i10 + i20 + i30 is a real number?

Show that 1 + i10 + i20 + i30 is a real number?

#### Solve the quadratic equations by factorization method only x2 + (1 – 2i)x – 2i = 0

Solve the quadratic equations by factorization method only x2 + (1 – 2i)x – 2i = 0

#### Solve the quadratic equations by factorization method only x2 + 10ix – 21 = 0

Solve the quadratic equations by factorization method only x2 + 10ix – 21 = 0