Find the \( 10^{th}\) term of the G.P. \( \dfrac{-3}{4}, \dfrac{1}{2}, \dfrac{-1}{3}, \dfrac{2}{9}, ….\)

Asked by Sakshi | 1 year ago |  113

1 Answer

Solution :-

We know that,

t1 = a = \( \dfrac{-3}{4}\), r = \(\dfrac{ (\dfrac{1}{2}) }{ (\dfrac{-3}{4})}\)

=\(\dfrac{ 1}{2} × \dfrac{-4}{3} = \dfrac{-2}{3}\)

By using the formula,

Tn = arn-1

T10 = \( \dfrac{-3}{4}( \dfrac{-2}{3})^{10-1} \)

=  \(\dfrac{ 1}{2}(\dfrac{2}{3})^8\)

Answered by Sakshi | 1 year ago

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