Find the $$10^{th}$$ term of the G.P. $$\dfrac{-3}{4}, \dfrac{1}{2}, \dfrac{-1}{3}, \dfrac{2}{9}, ….$$

Asked by Sakshi | 1 year ago |  113

##### Solution :-

We know that,

t1 = a = $$\dfrac{-3}{4}$$, r = $$\dfrac{ (\dfrac{1}{2}) }{ (\dfrac{-3}{4})}$$

=$$\dfrac{ 1}{2} × \dfrac{-4}{3} = \dfrac{-2}{3}$$

By using the formula,

Tn = arn-1

T10 = $$\dfrac{-3}{4}( \dfrac{-2}{3})^{10-1}$$

=  $$\dfrac{ 1}{2}(\dfrac{2}{3})^8$$

Answered by Sakshi | 1 year ago

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