Find the 12th term of the G.P. 1/a3x3 , ax, a5x5, …

Find the \( 12^{th}\) term of the G.P. \( \dfrac{1}{a^3x^3} , ax, a^5x^5, …\)

Asked by Sakshi | 1 year ago |  140
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1 Answer

Solution :-

We know that,

t1 = a =\( \dfrac{ 1}{a^3x^3}\), r = \( \dfrac{ ax}{a^3x^3}\) = ax (a3x3) = a4x4

By using the formula,

Tn = arn-1

T12 = \(\dfrac{ 1}{a^3x^3 (a^4x^4)^{12-1}}\)

= \( \dfrac{ 1}{a^3x^3 (a^4x^4)^{11}}\)

= (ax)41

Answered by Sakshi | 1 year ago
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