Which term of the progression 18, -12, 8, … is $$\dfrac{512}{729}$$ ?

Asked by Sakshi | 1 year ago |  65

##### Solution :-

By using the formula,

Tn = arn-1

a = 18

r = $$\dfrac{-12}{18}$$

$$\dfrac{-2}{3}$$

Tn =$$\dfrac{512}{729}$$

n = ?

Tn = arn-1

8 = n – 1

n = 8 + 1

= 9

9th term of the Progression is $$\dfrac{512}{729}$$

Answered by Sakshi | 1 year ago

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