Find the $$4^{th} term$$ from the end of the G.P. $$\dfrac{ 1}{2}, \dfrac{1}{6}, \dfrac{1}{18}, \dfrac{1}{54}, … , \dfrac{1}{4374}$$

Asked by Sakshi | 1 year ago |  88

##### Solution :-

The nth term from the end is given by:

Given: last term, l = $$\dfrac{1}{4374}$$

= $$\dfrac{1}{6} × \dfrac{2}{1}$$

$$\dfrac{1}{3}$$

n = 4

a4 =  $$\dfrac{ \dfrac{1}{4374}}{ (\dfrac{3}{1})^3}$$

= $$\dfrac{1}{4374}$$× 33

= $$\dfrac{1}{4374}$$ × 27

$$\dfrac{1}{162}$$

4th term from last is$$\dfrac{1}{162}$$.

Answered by Sakshi | 1 year ago

### Related Questions

#### Construct a quadratic in x such that A.M. of its roots is A and G.M. is G.

Construct a quadratic in x such that A.M. of its roots is A and G.M. is G.

#### Find the two numbers whose A.M. is 25 and GM is 20.

Find the two numbers whose A.M. is 25 and GM is 20.

#### If a is the G.M. of 2 and 1/4 find a.

If a is the G.M. of 2 and $$\dfrac{1}{4}$$ find a.

#### Find the geometric means of the following pairs of numbers

Find the geometric means of the following pairs of numbers:

(i) 2 and 8

(ii) a3b and ab3

(iii) –8 and –2

Insert 5 geometric means between $$\dfrac{32}{9}$$ and $$\dfrac{81}{2}$$.