The nth term from the end is given by:
Given: last term, l = \( \dfrac{1}{4374}\)
= \(\dfrac{1}{6} × \dfrac{2}{1}\)
= \( \dfrac{1}{3}\)
n = 4
a4 = \( \dfrac{ \dfrac{1}{4374}}{ (\dfrac{3}{1})^3}\)
= \( \dfrac{1}{4374}\)× 33
= \( \dfrac{1}{4374}\) × 27
= \( \dfrac{1}{162}\)
4th term from last is\( \dfrac{1}{162}\).
Answered by Sakshi | 1 year agoConstruct a quadratic in x such that A.M. of its roots is A and G.M. is G.
Find the geometric means of the following pairs of numbers:
(i) 2 and 8
(ii) a3b and ab3
(iii) –8 and –2
Insert 5 geometric means between \( \dfrac{32}{9}\) and \( \dfrac{81}{2}\).