Find the sum of the geometric progressions 1, -1/2, 1/4, -1/8, …

Find the sum of the geometric progressions \( 1, \dfrac{-1}{2}, \dfrac{1}{4}, \dfrac{-1}{8}, …\)

Asked by Sakshi | 1 year ago |  88
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Class 11 Maths Sequences and Series         Add Answer

1 Answer

Solution :-

Given:

a = 1, r =\( \dfrac{ (\dfrac{-1}{2})}{1 }\)= \( \dfrac{-1}{2}\)

Now let us substitute the values in

=\( \dfrac{1}{(1 – (\dfrac{-1}{2}))}\)

= \(\dfrac{ 1}{(\dfrac{3}{2})}\)

= \( \dfrac{2}{3}\)

Answered by Sakshi | 1 year ago
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