Find the sum of geometric series  $$\dfrac{ 2}{9} – \dfrac{1}{3} + \dfrac{1}{2} – \dfrac{3}{4} + …$$to 5 terms

Asked by Sakshi | 1 year ago |  72

Solution :-

Given:

a = $$\dfrac{2}{9}$$

r = $$\dfrac{(\dfrac{-1}{3})}{(\dfrac{2}{9})}=\dfrac{-3}{2}$$

n = 5

By using the formula,

Sum of GP for n terms = $$\dfrac{ a(1 – r^n )}{(1 – r)}$$

= $$\dfrac{2}{9} (\dfrac{275}{32}) × \dfrac{2}{5}$$

$$\dfrac{55}{72}$$

Answered by Sakshi | 1 year ago

Related Questions

Construct a quadratic in x such that A.M. of its roots is A and G.M. is G.

Construct a quadratic in x such that A.M. of its roots is A and G.M. is G.

Find the two numbers whose A.M. is 25 and GM is 20.

Find the two numbers whose A.M. is 25 and GM is 20.

If a is the G.M. of 2 and 1/4 find a.

If a is the G.M. of 2 and $$\dfrac{1}{4}$$ find a.

Find the geometric means of the following pairs of numbers

Find the geometric means of the following pairs of numbers:

(i) 2 and 8

(ii) a3b and ab3

(iii) –8 and –2

Insert 5 geometric means between $$\dfrac{32}{9}$$ and $$\dfrac{81}{2}$$.