Find the sum of geometric series  \(\dfrac{ 2}{9} – \dfrac{1}{3} + \dfrac{1}{2} – \dfrac{3}{4} + … \)to 5 terms

Asked by Sakshi | 1 year ago |  72

1 Answer

Solution :-

Given:

a = \( \dfrac{2}{9}\)

r = \( \dfrac{(\dfrac{-1}{3})}{(\dfrac{2}{9})}=\dfrac{-3}{2}\)

n = 5

By using the formula,

Sum of GP for n terms = \(\dfrac{ a(1 – r^n )}{(1 – r)}\)

= \( \dfrac{2}{9} (\dfrac{275}{32}) × \dfrac{2}{5}\)

\( \dfrac{55}{72}\)

Answered by Sakshi | 1 year ago

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