Find the sum of geometric series \( \dfrac{3}{5} + \dfrac{4}{5^2} + \dfrac{3}{5^3} +\dfrac{ 4}{5^4} + … \)to 2n terms

Asked by Sakshi | 1 year ago |  78

1 Answer

Solution :-

The series can be written as:

Firstly let us consider 3(\( \dfrac{1}{5}\) + \( \dfrac{1}{5^3}\) + \( \dfrac{1}{5^5}\)+ … to n terms)

So, a = \( \dfrac{1}{5}\)

r = \( \dfrac{1}{5^2}\) = \( \dfrac{1}{25}\)

Now, Let us consider 4 (\( \dfrac{1}{5^2}\) + \( \dfrac{1}{5^4}\) + \( \dfrac{1}{5^6}\) + … to n terms)

So, a = \( \dfrac{1}{25}\)

r= \( \dfrac{1}{5^2}\) = \( \dfrac{1}{25}\)

Answered by Sakshi | 1 year ago

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