Find the sum of geometric series $$\dfrac{3}{5} + \dfrac{4}{5^2} + \dfrac{3}{5^3} +\dfrac{ 4}{5^4} + …$$to 2n terms

Asked by Sakshi | 1 year ago |  78

##### Solution :-

The series can be written as:

Firstly let us consider 3($$\dfrac{1}{5}$$ + $$\dfrac{1}{5^3}$$ + $$\dfrac{1}{5^5}$$+ … to n terms)

So, a = $$\dfrac{1}{5}$$

r = $$\dfrac{1}{5^2}$$ = $$\dfrac{1}{25}$$

Now, Let us consider 4 ($$\dfrac{1}{5^2}$$ + $$\dfrac{1}{5^4}$$ + $$\dfrac{1}{5^6}$$ + … to n terms)

So, a = $$\dfrac{1}{25}$$

r= $$\dfrac{1}{5^2}$$ = $$\dfrac{1}{25}$$

Answered by Sakshi | 1 year ago

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