Given:
Sum of GP = 728
Where, a = 2, r = \( \dfrac{6}{2}\) = 3, n = ?
By using the formula,
Sum of GP for n terms =
728 = \(\dfrac{ 2 (3^n – 1)}{(3-1)}\)
728 =\( \dfrac{ 2 (3^n – 1)}{2}\)
728 = 3n – 1
729 = 3n
36 = 3n
6 = n
6 terms are required to make a sum equal to 728
Answered by Sakshi | 1 year agoConstruct a quadratic in x such that A.M. of its roots is A and G.M. is G.
Find the geometric means of the following pairs of numbers:
(i) 2 and 8
(ii) a3b and ab3
(iii) –8 and –2
Insert 5 geometric means between \( \dfrac{32}{9}\) and \( \dfrac{81}{2}\).