Find the sum of the series to infinity $$1 – \dfrac{1}{3} + \dfrac{1}{3^2} – \dfrac{1}{3^3} + \dfrac{1}{3^4} + … ∞$$

Asked by Sakshi | 1 year ago |  61

##### Solution :-

Where, a = 1, r =$$\dfrac{-1}{3}$$

By using the formula,

S =$$\dfrac{a}{(1 – r)}$$

= $$\dfrac{ 1 }{ (1 – (\dfrac{-1}{3}))}$$

= $$\dfrac{ 1}{ (\dfrac{4}{3})}$$

$$\dfrac{3}{4}$$

Answered by Sakshi | 1 year ago

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