Find the sum of the series to infinity \( 1 – \dfrac{1}{3} + \dfrac{1}{3^2} – \dfrac{1}{3^3} + \dfrac{1}{3^4} + … ∞\)

Asked by Sakshi | 1 year ago |  61

1 Answer

Solution :-

Where, a = 1, r =\(\dfrac{-1}{3}\)

By using the formula,

S =\( \dfrac{a}{(1 – r)}\)

= \(\dfrac{ 1 }{ (1 – (\dfrac{-1}{3}))}\)

= \(\dfrac{ 1}{ (\dfrac{4}{3})}\)

\( \dfrac{3}{4}\)

Answered by Sakshi | 1 year ago

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