a(b2 + c2) = c(a2 + b2)
Given that a, b, c are in GP.
By using the property of geometric mean,
b2 = ac
Let us consider LHS: a(b2 + c2)
Now, substituting b2 = ac, we get
a(ac + c2)
a2c + ac2
c(a2 + ac)
Substitute ac = b2 we get,
c(a2 + b2) = RHS
LHS = RHS
Hence proved.
Answered by Aaryan | 1 year agoConstruct a quadratic in x such that A.M. of its roots is A and G.M. is G.
Find the geometric means of the following pairs of numbers:
(i) 2 and 8
(ii) a3b and ab3
(iii) –8 and –2
Insert 5 geometric means between \( \dfrac{32}{9}\) and \( \dfrac{81}{2}\).