If a, b, c are in G.P., prove that are also in G.P a3, b3, c3

Asked by Sakshi | 1 year ago |  69

1 Answer

Solution :-

a3, b3, c3

Given that a, b, c are in GP.

By using the property of geometric mean,

b2 = ac

on squaring both the sides we get,

(b2)3 = (ac)3

(b2)3 = a3c3

(b3)2 = a3c3

a3, b3, c3 are in G.P.

Answered by Aaryan | 1 year ago

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