(i) \( \dfrac{-\pi}{4}\)
Let the slope of the line be ‘m’
Where, m = tan θ
So, the slope of Line is m = tan (\( \dfrac{-\pi}{4}\))
= – 1
The slope of the line is – 1.
(ii) \( \dfrac{2\pi}{3}\)
Let the slope of the line be ‘m’
Where, m = tan θ
So, the slope of Line is m = tan (\( \dfrac{2\pi}{3}\))
tan (\( \dfrac{2\pi}{3}\)) = \( -\sqrt{3}\)
The slope of the line is \( -\sqrt{3}\)
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