Find the slopes of a line

(i) which bisects the first quadrant angle

(ii) which makes an angle of 30° with the positive direction of y – axis measured anticlockwise.

Asked by Aaryan | 1 year ago |  90

#### 1 Answer

##### Solution :-

(i) Which bisects the first quadrant angle?

Given: Line bisects the first quadrant

We know that, if the line bisects in the first quadrant, then the angle must be between line and the positive direction of x – axis.

Since, angle =$$\dfrac{90}{2}$$ = 45°

By using the formula,

The slope of the line, m = tan θ

The slope of the line for a given angle is m = tan 45°

So, m = 1

The slope of the line is 1.

(ii) Which makes an angle of 30° with the positive direction of y – axis measured anticlockwise?

Given: The line makes an angle of 30° with the positive direction of y – axis.

We know that, angle between line and positive side of axis = 90° + 30° = 120°

By using the formula,

The slope of the line, m = tan θ

The slope of the line for a given angle is m = tan 120°

So, m = $$-\sqrt{3}$$

The slope of the line is $$-\sqrt{3}$$

Answered by Aaryan | 1 year ago

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