Find the equation of the parallel to x–axis and passing through (3, –5).

Asked by Aaryan | 1 year ago |  103

1 Answer

Solution :-

Given: A line which is parallel to x–axis and passing through (3, –5)

By using the formula,

The equation of line: [y – y1 = m(x – x1)]

We know that the parallel lines have equal slopes

And, the slope of x–axis is always 0

Then

The slope of line, m = 0

Coordinates of line are (x1, y1) = (3, –5)

The equation of line = y – y1 = m(x – x1)

Now, substitute the values, we get

y – (– 5) = 0(x – 3)

y + 5 = 0

The equation of line is y + 5 = 0

Answered by Sakshi | 1 year ago

Related Questions

Find the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.

Class 11 Maths Straight Lines View Answer

Prove that the points (2, -1), (0, 2), (2, 3) and (4, 0) are the coordinates of the vertices of a parallelogram and find the angle between its diagonals.

Class 11 Maths Straight Lines View Answer

Find the acute angle between the lines 2x – y + 3 = 0 and x + y + 2 = 0.

Class 11 Maths Straight Lines View Answer

Find the angles between pairs of straight lines 3x – y + 5 = 0 and x – 3y + 1 = 0

Class 11 Maths Straight Lines View Answer

Find the angles between pairs of straight lines 3x + y + 12 = 0 and x + 2y – 1 = 0

Class 11 Maths Straight Lines View Answer