Find the equation of a straight line with slope $$\dfrac{-1}{3}$$ and y – intercept – 4

Asked by Aaryan | 1 year ago |  74

##### Solution :-

With slope $$\dfrac{-1}{3}$$ and y – intercept – 4

The slope is $$\dfrac{-1}{3}$$ and the coordinates are (0, – 4)

Now, the required equation of line is

y = mx + c

Substitute the values, we get

y = $$\dfrac{-1}{3}x$$ – 4

3y + x = – 12

Answered by Aaryan | 1 year ago

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