Find the equation of a straight line with slope – 1/ 3 and y – intercept – 4

Find the equation of a straight line with slope \( \dfrac{-1}{3}\) and y – intercept – 4

Asked by Aaryan | 1 year ago |  74
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Solution :-

With slope \( \dfrac{-1}{3}\) and y – intercept – 4

The slope is \( \dfrac{-1}{3}\) and the coordinates are (0, – 4)

Now, the required equation of line is

y = mx + c

Substitute the values, we get

y = \( \dfrac{-1}{3}x\) – 4

3y + x = – 12

Answered by Aaryan | 1 year ago
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