Given, A straight line passing through the point (6, 2) and the slope is – 3

By using the formula,

The equation of line is [y – y_{1} = m(x – x_{1})]

Here, the line is passing through (6, 2)

It is given that, the slope of line, m = –3

Coordinates of line are (x_{1}, y_{1}) = (6,2)

The equation of line = y – y_{1} = m(x – x_{1})

Now, substitute the values, we get

y – 2 = – 3(x – 6)

y – 2 = – 3x + 18

y + 3x – 20 = 0

The equation of line is 3x + y – 20 = 0

Answered by Sakshi | 2 years agoFind the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.

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