Find the equation of the straight line passing through the point (6, 2) and having slope – 3.

Asked by Aaryan | 2 years ago |  84

##### Solution :-

Given, A straight line passing through the point (6, 2) and the slope is – 3

By using the formula,

The equation of line is [y – y1 = m(x – x1)]

Here, the line is passing through (6, 2)

It is given that, the slope of line, m = –3

Coordinates of line are (x1, y1) = (6,2)

The equation of line = y – y1 = m(x – x1)

Now, substitute the values, we get

y – 2 = – 3(x – 6)

y – 2 = – 3x + 18

y + 3x – 20 = 0

The equation of line is 3x + y – 20 = 0

Answered by Sakshi | 2 years ago

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