Given, A straight line passing through the point (6, 2) and the slope is – 3
By using the formula,
The equation of line is [y – y1 = m(x – x1)]
Here, the line is passing through (6, 2)
It is given that, the slope of line, m = –3
Coordinates of line are (x1, y1) = (6,2)
The equation of line = y – y1 = m(x – x1)
Now, substitute the values, we get
y – 2 = – 3(x – 6)
y – 2 = – 3x + 18
y + 3x – 20 = 0
The equation of line is 3x + y – 20 = 0
Answered by Sakshi | 1 year agoFind the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.
Prove that the points (2, -1), (0, 2), (2, 3) and (4, 0) are the coordinates of the vertices of a parallelogram and find the angle between its diagonals.
Find the acute angle between the lines 2x – y + 3 = 0 and x + y + 2 = 0.
Find the angles between pairs of straight lines 3x – y + 5 = 0 and x – 3y + 1 = 0
Find the angles between pairs of straight lines 3x + y + 12 = 0 and x + 2y – 1 = 0