Find the equation of the line passing through $$(2, 2\sqrt{3})$$ and inclined with x – axis at an angle of 75°

Asked by Aaryan | 1 year ago |  59

##### Solution :-

Given:

A line which is passing through $$(2, 2\sqrt{3})$$, the angle is 75°

By using the formula,

The equation of line is [y – y1 = m(x – x1)]

Here, angle, θ = 75°

The slope of the line, m = tan θ

m = tan 75°

= 3.73 = $$2 + \sqrt{3}$$

The line passing through (x1, y1) =$$(2, 2\sqrt{3})$$

The required equation of the line is y – y1 = m(x – x1)

Now, substitute the values, we get

$$y – 2\sqrt{3} = 2 + \sqrt{3} (x – 2)$$

$$y – 2\sqrt{3} = (2 + \sqrt{3})x – 7.46$$

$$(2 + \sqrt{3})x – y – 4 = 0$$

The equation of the line is $$(2 + \sqrt{3})x – y – 4 = 0$$

Answered by Sakshi | 1 year ago

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