Given:
A line which is passing through \( (2, 2\sqrt{3})\), the angle is 75°
By using the formula,
The equation of line is [y – y1 = m(x – x1)]
Here, angle, θ = 75°
The slope of the line, m = tan θ
m = tan 75°
= 3.73 = \( 2 + \sqrt{3}\)
The line passing through (x1, y1) =\( (2, 2\sqrt{3})\)
The required equation of the line is y – y1 = m(x – x1)
Now, substitute the values, we get
\( y – 2\sqrt{3} = 2 + \sqrt{3} (x – 2)\)
\( y – 2\sqrt{3} = (2 + \sqrt{3})x – 7.46\)
\( (2 + \sqrt{3})x – y – 4 = 0\)
The equation of the line is \( (2 + \sqrt{3})x – y – 4 = 0\)
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