**(i) **Cutting off intercepts 3 and 2 from the axes.

Given:

a = 3, b = 2

Let us find the equation of line cutoff intercepts from the axes.

By using the formula,

The equation of the line is \( \dfrac{ x}{a} + \dfrac{y}{b} = 1\)

\( \dfrac{ x}{3} + \dfrac{y}{2} = 1\)

By taking LCM,

2x + 3y = 6

∴ The equation of line cut off intercepts 3 and 2 from the axes is 2x + 3y = 6

**(ii) **Cutting off intercepts -5 and 6 from the axes.

Given:

a = -5, b = 6

Let us find the equation of line cutoff intercepts from the axes.

By using the formula,

The equation of the line is \( \dfrac{ x}{a} + \dfrac{y}{b} = 1\)

\( \dfrac{ x}{-5} + \dfrac{y}{6} = 1\)

By taking LCM,

6x – 5y = -30

The equation of line cut off intercepts 3 and 2 from the axes is 6x – 5y = -30

Answered by Aaryan | 1 year agoFind the angle between the line joining the points (2, 0), (0, 3) and the line x + y = 1.

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