(i) Cutting off intercepts 3 and 2 from the axes.
Given:
a = 3, b = 2
Let us find the equation of line cutoff intercepts from the axes.
By using the formula,
The equation of the line is \( \dfrac{ x}{a} + \dfrac{y}{b} = 1\)
\( \dfrac{ x}{3} + \dfrac{y}{2} = 1\)
By taking LCM,
2x + 3y = 6
∴ The equation of line cut off intercepts 3 and 2 from the axes is 2x + 3y = 6
(ii) Cutting off intercepts -5 and 6 from the axes.
Given:
a = -5, b = 6
Let us find the equation of line cutoff intercepts from the axes.
By using the formula,
The equation of the line is \( \dfrac{ x}{a} + \dfrac{y}{b} = 1\)
\( \dfrac{ x}{-5} + \dfrac{y}{6} = 1\)
By taking LCM,
6x – 5y = -30
The equation of line cut off intercepts 3 and 2 from the axes is 6x – 5y = -30
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