Given:

a = b and ab = 25

Let us find the equation of the line which cutoff intercepts on the axes.

a^{2} = 25

a = 5 [considering only positive value of intercepts]

By using the formula,

The equation of the line with intercepts a and b is \(\dfrac{ x}{a} + \dfrac{y}{b} = 1\)

\( \dfrac{ x}{5} + \dfrac{y}{5} = 1\)

By taking LCM

x + y = 5

The equation of line is x + y = 5

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