Find the equation of a line for which p = 4, α = 150°

Asked by Sakshi | 1 year ago |  51

##### Solution :-

p = 4, α = 150°

Given:

p = 4, α = 150°

The equation of the line in normal form is given by

Using the formula,

x cos α + y sin α = p

Now, substitute the values, we get

x cos 150° + y sin 150° = 4

cos (180° – θ) = – cos θ , sin (180° – θ) = sin θ

x cos(180° – 30°) + y sin(180° – 30°) = 4

– x cos 30° + y sin 30° = 4

$$\dfrac{-\sqrt{3}x}{2}+\dfrac{y}{2}=4$$

$$-\sqrt{3}x + y = 8$$

The equation of line in normal form is $$-\sqrt{3}x + y = 8$$

Answered by Aaryan | 1 year ago

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